To solve this inequality, we first need to find the sum of the arithmetic series from 3 to 8019.

The formula for the sum of an arithmetic series is:
Sn = n/2 * (a1 + an)
where:
Sn = sum of the first n terms
n = number of terms
a1 = first term
an = last term

In this case, a1 = 3, an = 8019, and the common difference d = 4 (since each term increases by 4).

To find the number of terms, we use the formula for the nth term of an arithmetic sequence:
an = a1 + (n-1)d
8019 = 3 + (n-1)4
8016 = 4n - 4
8020 = 4n
n = 2005

Now we can find the sum of the series:
Sn = 2005/2 * (3 + 8019)
Sn = 1002.5 * 8022
Sn = 8054455

Now we substitute this sum back into the original inequality:
(y - 3) * 8054455 < 2012/2013

Simplify the inequality:
8054455y - 24163365 < 2012/2013

Add 24163365 to both sides:
8054455y < 24163365 + 2012/2013

Now divide by 8054455 to solve for y:
y < (24163365 + 2012/2013) / 8054455

y < 3.005

Therefore, the solution to the inequality is y < 3.005.