To solve the equation \((x+2)(x-1) = 0\), we can use the zero product property. This property states that if the product of two factors is zero, then at least one of the factors must be zero. Therefore, we set each factor equal to zero and solve for \(x\):

1. \(x + 2 = 0\)
2. \(x - 1 = 0\)

Let's solve each equation separately:

1. \(x + 2 = 0\)
\[
x = -2
\]

2. \(x - 1 = 0\)
\[
x = 1
\]

So, the solutions to the equation \((x+2)(x-1) = 0\) are:
\[
x = -2 \quad \text{and} \quad x = 1
\]