It looks like there might be a typo in your equation. Let's clarify and correct it.

You wrote:
\[
(2x-3)^{10} = (3-2x0)^9
\]

The term \(2x0\) seems incorrect. If you meant \(2x\), then the equation should be:
\[
(2x-3)^{10} = (3-2x)^9
\]

However, if you meant \(2x \cdot 0\), then the right-hand side simplifies to 3:
\[
(2x-3)^{10} = 3^9
\]

Let's consider both cases:

### Case 1: \( (2x-3)^{10} = (3-2x)^9 \)

This equation is quite complex and doesn't have a straightforward solution. We can try to solve it by equating the bases if possible, but it might not lead to a simple solution.

### Case 2: \( (2x-3)^{10} = 3^9 \)

In this case, we can solve for \(x\) by taking the 10th root of both sides:
\[
2x - 3 = 3^{9/10}
\]

Now, solve for \(x\):
\[
2x = 3 + 3^{9/10}
\]
\[
x = \frac{3 + 3^{9/10}}{2}
\]

This gives us the value of \(x\) in terms of a numerical expression.

If you meant something else, please provide more context or correct the equation, and I'd be happy to help further!