It seems like you've written the equation twice, but I'll work with the equation \( X(x + 3) - 2x - 6 = 0 \) to help you solve it.

First, distribute the \( X \) in the expression:

\[ X(x + 3) = Xx + 3X. \]

So the equation becomes:

\[ Xx + 3X - 2x - 6 = 0. \]

Combine like terms:

\[ (X - 2)x + 3X - 6 = 0. \]

This is a linear equation in terms of \( x \). To solve for \( x \), first substitute the term with \( x \), \( (X - 2)x \), to one side, and the constant terms on the other side:

\[ (X - 2)x = -3X + 6. \]

Now, solve for \( x \) by dividing both sides by \( (X - 2) \), assuming \( X \neq 2 \):

\[ x = \frac{-3X + 6}{X - 2}. \]

This gives the solution for \( x \) in terms of \( X \), as long as \( X \neq 2 \) (since dividing by zero is undefined). If \( X = 2 \), the equation becomes \( 0 \cdot x + 6 - 6 = 0 \), which simplifies to \( 0 = 0 \), implying that any value of \( x \) is a solution (the equation holds true for all \( x \)).