PTHH: Zn + H2SO4 → ZnSO4 + H2
nZn=19,565=0,3(mol)nZn=19,565=0,3(mol)
nH2SO4=0,25×2,4=0,6(mol)nH2SO4=0,25×2,4=0,6(mol)
Theo PT: nZn=nH2SO4nZn=nH2SO4
Theo bài: nZn=12nH2SO4nZn=12nH2SO4
Vì 12<112<1 ⇒ HCl dư
Theo PT: nH2=nZn=0,3(mol)nH2=nZn=0,3(mol)
⇒VH2=0,3×22,4=6,72(l)⇒VH2=0,3×22,4=6,72(l)
Vì HS=90%HS=90% ⇒VH2tt=6,72×90%=6,048(l)