The equation you provided is a quadratic equation in two variables, x and y. It can be written as:

(x+1)^2 + (y - 2/3)^2 = 0

However, this equation does not have any real solutions because the sum of two squares cannot be zero unless both squares are zero individually. In this case, for the equation to hold true, both (x+1)^2 and (y - 2/3)^2 would have to be zero, which is not possible for real numbers x and y.