To solve the equation 6x(5x+3)+3x(1-10x)=7, we can start by simplifying the equation:

First, distribute 6x to (5x+3) and distribute 3x to (1-10x):

30x^2 + 18x + 3x - 30x^2 = 7

Combine like terms:

21x + 3x - 30x^2 = 7

24x - 30x^2 = 7

Rearrange the equation to set it equal to zero:

30x^2 - 24x + 7 = 0

Now, we can solve this quadratic equation. However, it does not factor nicely, so we will use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 30, b = -24, and c = 7. Plugging in these values, we get:

x = (-(-24) ± √((-24)^2 - 4(30)(7))) / (2(30))

Simplifying further:

x = (24 ± √(576 - 840)) / 60

x = (24 ± √(-264)) / 60

Since the discriminant (b^2 - 4ac) is negative, the quadratic equation has no real solutions. Therefore, there is no solution to the given equation.