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Cho tam giác ABC nhọn, đường cao AH, kẻ HM vuông AB, HN vuông AC .Chứng minh rằng √2 AC ≥ AH+HC

Cho tam giác ABC nhọn ,đg cao AH ,kẻ HM vuông AB, HN vuông AC .Chứng minh rằng √2 AC ≥ AH+HC

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Tham khảo câu trả lời từ Trợ lý ảo Lazi
Ta có:
$\angle HAM = \angle HAB + \angle BAM = \angle HAB + \angle BAC = \angle HAC$
$\angle HAN = \angle HAC + \angle CAN = \angle HAC + \angle CAB = \angle HAB$
Vậy $\triangle HAM \sim \triangle HAN$
Do đó $\frac{HM}{HN} = \frac{HA}{HA+HC}$
Mà $\frac{HM}{HN} = \frac{AM}{AN} = \frac{AC}{AC+BC}$
Vậy $\frac{AC}{AC+BC} = \frac{HA}{HA+HC}$
$\Rightarrow AC(HA+HC) = (AC+BC)HA$
$\Rightarrow AC.HA + AC.HC = AC.HA + BC.HA$
$\Rightarrow AC.HC = BC.HA$
$\Rightarrow \frac{AC}{HA} = \frac{HA}{HC}$
$\Rightarrow \frac{AC}{HA} = \frac{HA+HC}{HC}$
$\Rightarrow \frac{AC}{HA} = \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} - 1 = \frac{AH+HC}{HC} - 1$
$\Rightarrow \frac{AC-HA}{HA} = \frac{AH}{HC}$
$\Rightarrow \frac{AC}{HA} - \frac{HA}{HA} = \frac{AH}{HC}$
$\Rightarrow \frac{AC}{HA} - \frac{HA}{HA} = \frac{AH}{HC}$
$\Rightarrow \frac{AC}{HA} - 1 = \frac{AH}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
$\Rightarrow \frac{AC}{HA} \geq \frac{AH+HC}{HC}$
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