Tìm x

To solve the equation 9^x + 4 - 4×3^x + 5 + 27 = 0, we can simplify it by combining like terms:

9^x - 4×3^x + 36 = 0

Now, let's substitute a variable to simplify the equation further. Let's say u = 3^x.

Now, we can rewrite the equation as:

u^2 - 4u + 36 = 0

To solve this quadratic equation, we can use the quadratic formula:

u = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = -4, and c = 36. Substituting these values into the quadratic formula, we get:

u = (-(-4) ± √((-4)^2 - 4(1)(36))) / (2(1))
u = (4 ± √(16 - 144)) / 2
u = (4 ± √(-128)) / 2

Since we have a negative value under the square root, there are no real solutions for u. Therefore, there are no real solutions for x in the original equation.