The given equation is a quadratic equation in the form of y = ax^2 + bx + c, where a = 1, b = -4, and c = 11.

To find the vertex of the parabola represented by this equation, we can use the formula x = -b/2a.

Substituting the values, we have x = -(-4)/(2*1) = 4/2 = 2.

To find the y-coordinate of the vertex, we substitute x = 2 into the equation:

y = (2)^2 - 4(2) + 11
y = 4 - 8 + 11
y = 7

Therefore, the vertex of the parabola is (2, 7).