It seems like you have two equations, but there's a small formatting issue. The equations you've written are:

1. \( 4x + 7y = 18 \)
2. \( 3x - y = 1 \)

Let's solve this system of equations step-by-step.

We'll use substitution or elimination. In this case, I'll use the substitution method. From the second equation, we can express \(y\) in terms of \(x\):

\[
3x - y = 1 \quad \Rightarrow \quad y = 3x - 1
\]

Now, we can substitute \(y\) into the first equation:

\[
4x + 7(3x - 1) = 18
\]

Now distribute \(7\):

\[
4x + 21x - 7 = 18
\]

Combine like terms:

\[
25x - 7 = 18
\]

Add \(7\) to both sides:

\[
25x = 25
\]

Now divide by \(25\):

\[
x = 1
\]

Now that we have \(x\), substitute it back to find \(y\):

\[
y = 3(1) - 1 = 3 - 1 = 2
\]

Thus, the solution to the system of equations is:

\[
\boxed{(1, 2)}
\]

So, \(x = 1\) and \(y = 2\).