GIÚP VS Ạ ----- Nội dung ảnh ----- Dạng 1: Thực hiện phép tính Bài 1: Thực hiện phép tính 1) \( \frac{2}{5} + \frac{3}{8} \) 2) \( \frac{1}{3} - \frac{2}{10} \) 3) \( \frac{3}{5} + \frac{4}{7} \) 4) \( \frac{4}{2} + \frac{9}{8} \) 5) \( \frac{1}{2} + \frac{5}{4} \) 6) \( 27 + \frac{1}{4} \) 7) \( -5 + \frac{3}{4} \) 8) \( \frac{5}{3} + \frac{7}{4} \) 9) \( -\frac{3}{4} \) 10) \( \frac{3}{4} - \frac{5}{2} \) 11) \( \frac{2}{3} + \frac{1}{4} \) 12) \( \frac{1}{2} - \frac{3}{5} \) 13) \( \frac{5}{4} + \frac{-\frac{3}{2}}{12} + \frac{4}{4} \) 14) \( \frac{3}{2} + \frac{-\frac{1}{2}}{1} + \frac{2}{1} \) 15) \( \frac{1}{2} \times \frac{-3}{3} \) 16) \( 6 + \frac{3}{7} \) Bài 2: Thực hiện phép tính 1) \( \frac{-2}{3} + \frac{1}{2} \) 2) \( \frac{1}{7} + \frac{1}{4} \) 3) \( \frac{9}{10} - \frac{4}{5} + 1 \) 4) \( \frac{9}{5} - 5 + \frac{2}{3} \) 5) \( \frac{3}{2} - \frac{1}{3} \) 6) \( \frac{3}{4} + \frac{2}{3} \) Bài 3: Thực hiện phép tính 1) \( 12 + \frac{(1/2)^2}{5} \) 2) \( 18 + (1/2)^2 \) 3) \( 15 - \frac{(2/3)^2}{7} \) 4) \( \frac{1}{3} - \frac{2}{9} \) 5) \( \frac{1}{4} - (-\frac{1}{2})^2 \) 6) \( -3 + 2 + 6 \) Bài 4: Thực hiện phép tính 1) \( -(-1/3)^2 - 8/9 \) 2) \( 5 - 3 + (-\frac{1}{2})^2 \) 3) \( -(-1/3)^3 + \frac{8}{9} - \frac{26}{27} \) 4) \( -\frac{1}{7} + \left(\frac{2}{3}\right)^2 \) 5) \( (-\frac{1}{2})^2 + 1 \) 6) \( -(-\frac{2}{3})^2 - 2.5 \)
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22 Tham khảo câu trả lời từ Trợ lý ảo Lazi Dưới đây là kết quả của các phép tính trong bài: ### Bài 1: Thực hiện phép tính 1) \( 2 \frac{5}{8} + \frac{1}{6} = \frac{15}{24} + \frac{4}{24} = \frac{19}{24} \) 2) \( \frac{3}{5} + \frac{1}{10} = \frac{6}{10} + \frac{1}{10} = \frac{7}{10} \) 3) \( \frac{3}{5} - \frac{5}{4} = \frac{12}{20} - \frac{25}{20} = -\frac{13}{20} \) 4) \( \frac{2}{3} - \frac{1}{4} = \frac{8}{12} - \frac{3}{12} = \frac{5}{12} \) 5) \( \frac{5}{4} - \frac{1}{2} = \frac{5}{4} - \frac{2}{4} = \frac{3}{4} \) 6) \( \frac{-3}{4} + \frac{-1}{3} = -\frac{9}{12} - \frac{4}{12} = -\frac{13}{12} \) 7) \( \frac{7}{12} + \frac{1}{6} = \frac{7}{12} + \frac{2}{12} = \frac{9}{12} = \frac{3}{4} \) 8) \( 27 \frac{1}{12} = \frac{27 \cdot 12 + 1}{12} = \frac{325}{12} \) 9) \( 5 + \frac{3}{4} + \frac{3}{2} = 5 + \frac{3}{4} + \frac{6}{4} = 5 + \frac{9}{4} = \frac{29}{4} \) 10) \( \frac{5}{3} - \frac{2}{9} = \frac{15}{9} - \frac{2}{9} = \frac{13}{9} \) 11) \( \frac{5}{12} + \left(-\frac{3}{2}\right) + \frac{1}{2} = \frac{5}{12} - \frac{6}{12} + \frac{2}{12} = \frac{1}{12} \) 12) \( 2 \cdot 5 + \frac{3}{2} = 10 + \frac{3}{2} = \frac{20}{2} + \frac{3}{2} = \frac{23}{2} \) ### Bài 2: Thực hiện phép tính 1) \( \frac{2}{3} + \left( 1 \frac{3}{4} \right) = \frac{2}{3} + \frac{7}{4} = \frac{8}{12} + \frac{21}{12} = \frac{29}{12} \) 2) \( \frac{1}{7} - \left( \frac{6}{7} - \frac{1}{3} \right) = \frac{1}{7} - \left( \frac{18}{21} - \frac{7}{21} \right) = \frac{1}{7} - \frac{11}{21} = \frac{3}{21} - \frac{11}{21} = -\frac{8}{21} \) 3) \( \left(-\frac{1}{3}\right) \cdot 11 - 7 = -\frac{11}{3} - 7 = -\frac{11}{3} - \frac{21}{3} = -\frac{32}{3} \) 4) \( \left( \frac{3}{4} \right) + \frac{3}{4} \cdot 2 = \frac{3}{4} + \frac{3 \cdot 2}{4} = \frac{3}{4} + \frac{6}{4} = \frac{9}{4} \) 5) \( \left( \frac{9}{10} \right) + \left( 2 + \frac{5}{2} \right) = \frac{9}{10} + \frac{9}{2} = \frac{9}{10} + \frac{45}{10} = \frac{54}{10} = \frac{27}{5} \) 6) \( -\frac{3}{2} + 17 \div 24 = -\frac{3}{2} + \frac{17}{24} = -\frac{36}{24} + \frac{17}{24} = -\frac{19}{24} \) ### Bài 3: Thực hiện phép tính 1) \( 12 \cdot \left( \frac{1}{3} \right)^2 = 12 \cdot \frac{1}{9} = \frac{12}{9} = \frac{4}{3} \) 2) \( 18 \cdot \left( 1 \frac{1}{2} \right)^2 = 18 \cdot \left( \frac{3}{2} \right)^2 = 18 \cdot \frac{9}{4} = \frac{162}{4} = \frac{81}{2} \) 3) \( 15 \cdot \frac{2}{3} = 10 \) 4) \( 1 + 3^2 \cdot 2 \div 9 = 1 + 9 \cdot 2 \div 9 = 1 + 2 = 3 \) 5) \( \left(-\frac{3}{4}\right)^2 - \left(-\frac{9}{4}\right) = \frac{9}{16} + \frac{9}{4} = \frac{9}{16} + \frac{36}{16} = \frac{45}{16} \) 6) \( -\left(\frac{3}{2}\right)^2 = -\frac{9}{4} \) 7) \( 3 + \left(-6\right) = -3 \) ### Bài 4: Thực hiện phép tính 1) \( \frac{1}{3} + \frac{1}{3} - 8 + 9 = 2 - 8 + 9 = 3 \) 2) \( 5 \cdot \frac{1}{2} - \left( -\frac{1}{2} \right)^2 = \frac{5}{2} - \frac{1}{4} = \frac{10}{4} - \frac{1}{4} = \frac{9}{4} \) 3) \( -\left(-1\right)^3 + \frac{8}{27} = -(-1) + \frac{8}{27} = 1 + \frac{8}{27} = \frac{27}{27} + \frac{8}{27} = \frac{35}{27} \) 4) \( -\left( 1 \cdot -7 \right) - \frac{4}{9} \cdot -\left(\frac{2}{3}\right)^2 = 7 - \frac{4}{9} \cdot \frac{4}{9} = 7 - \frac{16}{81} = \frac{567}{81} - \frac{16}{81} = \frac{551}{81} \) 5) \( \left(-1\right)^2 - 1 + 2 = 1 - 1 + 2 = 2 \) 6) \( \left(-\frac{1}{2}\right)^2 - 5 = \frac{1}{4} - 5 = \frac{1 - 20}{4} = -\frac{19}{4} \) Nếu bạn cần hỗ trợ thêm hay chi tiết về từng bài, hãy cho tôi biết!