Tìm x, biết: \( 3(x - y)^2 - 2(x - y) + 3(3x - 1) = 1 \)

To solve the equation \( 3(x - y)^2 - 2(x - y) + 3(3x - 1) = 1 \), we can start by simplifying it.

Let \( z = x - y \). So the equation becomes:

\[ 3z^2 - 2z + 3(3x - 1) = 1. \]

Now we can expand the equation:

1. Substitute \( 3(3x - 1) \):

\[
3z^2 - 2z + 9x - 3 = 1.
\]

2. Move 1 to the left side:

\[
3z^2 - 2z + 9x - 4 = 0.
\]

Next, we need to express \( x \) in terms of \( z \) or \( y \) if needed. However, without further information about \( y \), we cannot determine a specific value for \( x \).

If you have additional constraints or values for \( y \), please provide them so we can continue solving for \( x \).