To simplify the expression \(-\frac{20}{28} - \frac{12}{32} + \frac{7}{196} - \frac{20}{28} - \frac{12}{32} + \frac{7}{196}\), let's first combine like terms.

Notice that there are two terms of each kind:

\[
-2 \cdot \frac{20}{28} - 2 \cdot \frac{12}{32} + 2 \cdot \frac{7}{196}
\]

Now, let's simplify each fraction:

1. \(\frac{20}{28} = \frac{5}{7}\) (by dividing the numerator and the denominator by 4),
2. \(\frac{12}{32} = \frac{3}{8}\) (by dividing by 4),
3. \(\frac{7}{196} = \frac{1}{28}\) (by dividing by 7).

Substituting back into the expression:

\[
-2 \cdot \frac{5}{7} - 2 \cdot \frac{3}{8} + 2 \cdot \frac{1}{28}
\]

Calculating each term separately:

1. \(-2 \cdot \frac{5}{7} = -\frac{10}{7}\)
2. \(-2 \cdot \frac{3}{8} = -\frac{6}{8} = -\frac{3}{4}\)
3. \(2 \cdot \frac{1}{28} = \frac{2}{28} = \frac{1}{14}\)

Now we need to add these three fractions:

\[
-\frac{10}{7} - \frac{3}{4} + \frac{1}{14}
\]

To do this, we find a common denominator. The least common multiple of the denominators \(7\), \(4\), and \(14\) is \(28\).

Now, we rewrite each fraction with a denominator of \(28\):

1. \(-\frac{10}{7} = -\frac{10 \cdot 4}{7 \cdot 4} = -\frac{40}{28}\)
2. \(-\frac{3}{4} = -\frac{3 \cdot 7}{4 \cdot 7} = -\frac{21}{28}\)
3. \(\frac{1}{14} = \frac{1 \cdot 2}{14 \cdot 2} = \frac{2}{28}\)

Now we combine these fractions:

\[
-\frac{40}{28} - \frac{21}{28} + \frac{2}{28} = \frac{-40 - 21 + 2}{28} = \frac{-59}{28}
\]

Thus, the simplified result of the expression is:

\[
\boxed{-\frac{59}{28}}
\]