It looks like you've written a system of equations, but there seems to be a formatting issue. Let's rewrite it for clarity:

1. \( 5x + 2y = 10 \)
2. \( -x - 3y = 11 \)

To solve this system of equations, we can use either the substitution method or the elimination method. Here, I'll use the elimination method.

First, let's align the equations:

\[
5x + 2y = 10
\]
\[
-x - 3y = 11
\]

To eliminate \( x \), we can multiply the second equation by 5:

\[
5(-x - 3y) = 5(11)
\]
\[
-5x - 15y = 55
\]

Now, add the two equations together:

\[
(5x + 2y) + (-5x - 15y) = 10 + 55
\]
\[
0x - 13y = 65
\]
\[
-13y = 65
\]

Solve for \( y \) by dividing both sides by -13:

\[
y = \frac{65}{-13}
\]
\[
y = -5
\]

Now substitute \( y = -5 \) back into one of the original equations to solve for \( x \). Using the first equation:

\[
5x + 2(-5) = 10
\]
\[
5x - 10 = 10
\]
\[
5x = 20
\]
\[
x = \frac{20}{5}
\]
\[
x = 4
\]

Thus, the solution to the system of equations is \( x = 4 \) and \( y = -5 \).