Bài 95 trang 45 sgk toán 7 - tập 1

Bài 95. Tính giá trị biểu thức: 
\(A =  - 5,13:\left( {5{5 \over {28}} - 1{8 \over 9}.1,25 + 1{{16} \over {63}}} \right)\)
\(B = \left( {3{1 \over 3}.1,9 + 19,5:4{1 \over 3}} \right).\left( {{{62} \over {75}} - {4 \over {25}}} \right)\)
Giải
\(\eqalign{
& A = - 5,13:\left( {5{5 \over {28}} - 1{8 \over 9}.1,25 + 1{{16} \over {63}}} \right) \cr
& = - 5,13:\left( {{{145} \over {28}} - {{17} \over 9}.{{125} \over {100}} + {{79} \over {63}}} \right) \cr
& = - 5,13:\left( {{{145} \over {28}} - {{17} \over 9}.{5 \over 4} + {{79} \over {63}}} \right) \cr
& = - 5,13:\left( {{{145} \over {28}} - {{85} \over {36}} + {{79} \over {63}}} \right) \cr
& = - 5,13:{{57} \over {14}} = - 5,13.{{14} \over {57}} \cr
& = {{ - 71,82} \over {57}} = -1,26 \cr} \)
\(\eqalign{
& B = \left( {3{1 \over 3}.1,9 + 19,5:4{1 \over 3}} \right).\left( {{{62} \over {75}} - {4 \over {25}}} \right) \cr
& = \left( {{{10} \over 3}.1,9 + 19,5:{{13} \over 3}} \right).\left( {} \right) \cr
& = \left( {{{19} \over 3} + {{58,5} \over {13}}} \right).{{50} \over {75}} \cr
& = \left( {{{19} \over 3} + 4,5} \right).{2 \over 3} \cr
& =