cosx + √3.sinx = √2
<=>1/2cosx+√3/2 sinx=√2/2
<=>cos π/3 cosx+sin π/3 sinx=√2/2
<=>cos(x- π/3)=cos π/4
<=>[x=7π/12+k2π
      [x=π/12+k2π

sinx + √3.cosx = 1
<=>1/2 sinx+√3/2cosx=1/2
<=>cosπ/3 sinx+sinπ/3cosx=1/2
<=> sin(x+π/3)=sinπ/6
<=>[x=-π/6+k2π
      [x=π/2+k2π