First, we have: 5^2+2=27(2nd)52+2=27(2nd) so we have number 7
Second, we have: 7^2+2=51(3rd)72+2=51(3rd) so we have number 1
Third, we have: 1^2+2=3(4th)12+2=3(4th) so we have number 3
Fourth, we have: 3^2+2=11(5th)32+2=11(5th) so we have number 1
So the sequence from the 6th number will be the numbers 3 and 1. Since 100 is an even number so the 100th-term number is 3