\[\frac{1}{{{a^2} + 2bc}} + \frac{1}{{{b^2} + 2ac}} + \frac{1}{{{c^2} + 2ab}} \ge 9\]., \(\frac{1}{{{a^2} + 2bc}} + \frac{1}{{{b^2} + 2ac}} + \frac{1}{{{c^2} + 2ab}} \ge 9\).