\(\begin{array}{l}
{m_{C{O_2}}} = m = 2,2g\\
{m_{{H_2}O}} = m = 1,08g\\
{n_{C{O_2}}} = \dfrac{{2,2}} = 0,05\,mol\\
{n_{{H_2}O}} = \dfrac{{1,08}} = 0,06\,mol\\
{n_C} = {n_{C{O_2}}} = 0,05\,mol\\
{n_H} = 2{n_{{H_2}O}} = 0,12\,mol\\
m = {m_C} + {m_H} = 0,05 \times 12 + 0,12 \times 1 = 0,72g\\
{n_C}:{n_H} = 0,05:0,12 = 5:12\\
 \Rightarrow CTPT\,:{C_5}{H_{12}}\\
{C_5}{H_{12}} + 8{O_2} \xrightarrow{t^0} 5C{O_2} + 6{H_2}O\\
{n_} = \dfrac{{0,05 \times 8}}{5} = 0,08\,mol\\
{V_} = 0,08 \times 22,4 = 1,792l
\end{array}\)
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