a) Vì ABCD là hình thang ( \(AB//CD\))

\(\Rightarrow\widehat{B}+\widehat{C}=180^o\)

mà \(\widehat{B}-\widehat{C}=50^o\)\(\Rightarrow\widehat{B}=\frac{180^o+50^o}{2}=115^o\)

\(\Rightarrow\widehat{C}=180^o-115^o=65^o\)

Vì \(AB//CD\)\(\Rightarrow\widehat{A}+\widehat{D}=180^o\)

mà \(\widehat{A}=\frac{1}{3}.\widehat{D}\)\(\Rightarrow\frac{1}{3}.\widehat{D}+\widehat{D}=180^o\)

\(\Rightarrow\frac{4}{3}.\widehat{D}=180^o\)\(\Rightarrow\widehat{D}=135^o\)\(\Rightarrow\widehat{A}=\frac{1}{3}.135^o=45^o\)

Vậy \(\widehat{A}=45^o\); \(\widehat{B}=115^o\); \(\widehat{C}=65^o\); \(\widehat{D}=135^o\)