1, √12/√5 – √3 2, 2 + √3/2 – √3 3, √2 + 1/√2 – 1 4, 3√2/√3 + 1
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54 Tham khảo câu trả lời từ Trợ lý ảo Lazi 1. To simplify √12/√5 – √3, we can start by rationalizing the denominator of the first term. √12/√5 can be written as (√12/√5) * (√5/√5) = √60/5. So, the expression becomes √60/5 – √3. To simplify further, we can factor the square root of 60. √60 = √(4 * 15) = √4 * √15 = 2√15. Therefore, the expression becomes 2√15/5 – √3. 2. To simplify 2 + √3/2 – √3, we can start by rationalizing the denominator of the second term. √3/2 can be written as (√3/2) * (√2/√2) = √6/2. So, the expression becomes 2 + √6/2 – √3. To simplify further, we can multiply the whole expression by 2/2 to get rid of the fraction. (2 * 2 + √6)/2 – √3 = (4 + √6)/2 – √3. 3. To simplify √2 + 1/√2 – 1, we can start by rationalizing the denominator of the second term. 1/√2 can be written as (1/√2) * (√2/√2) = √2/2. So, the expression becomes √2 + √2/2 – 1. To simplify further, we can combine the terms with the same denominator. (√2 + √2)/2 – 1 = (2√2)/2 – 1 = √2 – 1. 4. To simplify 3√2/√3 + 1, we can start by rationalizing the denominator of the first term. √3 can be written as (√3) * (√3/√3) = 3/√3. So, the expression becomes 3√2/(3/√3) + 1. To simplify further, we can multiply the numerator and denominator of the first term by √3. (3√2 * √3)/(3 * √3) + 1 = (3√6)/3 + 1. Simplifying further, we can cancel out the 3's in the numerator and denominator. √6 + 1.