(2xa-15) mũ 3 =(2 mũ 3 x 3 mũ 3-2 mũ 3 x 2 mũ 2) : 19 x 2

To solve this equation, we need to simplify both sides and then solve for the variable "a".

Starting with the left side of the equation:

(2xa - 15)^3

Using the formula for the cube of a binomial, we can expand this expression:

(2xa)^3 - 3(2xa)^2(15) + 3(2xa)(15)^2 - (15)^3

= 8x^3a^3 - 3(4x^2a^2)(15) + 3(2xa)(225) - 3375

= 8x^3a^3 - 180x^2a^2 + 675xa - 3375

Now let's simplify the right side of the equation:

(2^3 x 3^3 - 2^3 x 2^2) / (19 x 2)

= (8 x 27 - 8 x 4) / (19 x 2)

= (216 - 32) / (38)

= 184 / 38

= 92 / 19

Now we can set the left side equal to the right side and solve for "a":

8x^3a^3 - 180x^2a^2 + 675xa - 3375 = 92 / 19

This is a cubic equation in terms of "a". To solve it, we can either factor it or use numerical methods such as Newton's method or the bisection method. However, without further information or constraints, we cannot determine the exact value of "a" in this equation.