To solve the equation √(4x^2-20x+25)+2x=5, we can start by isolating the square root term on one side of the equation.

Subtracting 2x from both sides, we get:

√(4x^2-20x+25) = 5 - 2x

Now, we can square both sides of the equation to eliminate the square root:

(√(4x^2-20x+25))^2 = (5 - 2x)^2

Simplifying the left side:

4x^2-20x+25 = (5 - 2x)^2

Expanding the right side:

4x^2-20x+25 = 25 - 20x + 4x^2

Notice that the terms on both sides cancel out, leaving us with:

0 = 0

This equation is true for all values of x. Therefore, the original equation √(4x^2-20x+25)+2x=5 is an identity, meaning it holds true for all values of x.