This statement is not true.

To prove this, we can expand both expressions and compare them.

Expanding [2x-15]^5 using the binomial theorem, we get:

[2x-15]^5 = (5 choose 0)(2x)^5(-15)^0 + (5 choose 1)(2x)^4(-15)^1 + (5 choose 2)(2x)^3(-15)^2 + (5 choose 3)(2x)^2(-15)^3 + (5 choose 4)(2x)^1(-15)^4 + (5 choose 5)(2x)^0(-15)^5

Simplifying this expression, we get:

[2x-15]^5 = 32x^5 - 1200x^4 + 18000x^3 - 135000x^2 + 506250x - 759375

Expanding [2x-15]^3 using the binomial theorem, we get:

[2x-15]^3 = (3 choose 0)(2x)^3(-15)^0 + (3 choose 1)(2x)^2(-15)^1 + (3 choose 2)(2x)^1(-15)^2 + (3 choose 3)(2x)^0(-15)^3

Simplifying this expression, we get:

[2x-15]^3 = 8x^3 - 180x^2 + 1350x - 3375

As we can see, the two expressions are not equal. Therefore, [2x-15]^5 is not equal to [2x-15]^3.