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Bài tậpBài chưa trả lời

Trả lời bài tập giúp bạn nhé!

Tìm x, biết:

a, |3x +6|-12=x+1
b, |x-2|=|3x+5|
c, 12-4*|x+1/2|=0
d, |x-3|+2*|2x-6|=0
e, |4-x|=8-2x
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Tham khảo câu trả lời từ Trợ lý ảo Lazi
a) To solve this equation, we can split it into two cases based on the sign of the expression inside the absolute value.

Case 1: 3x + 6 is positive
In this case, the equation becomes 3x + 6 - 12 = x + 1.
Simplifying, we get 2x - 6 = x + 1.
Subtracting x from both sides, we have x = 7.

Case 2: 3x + 6 is negative
In this case, the equation becomes -(3x + 6) - 12 = x + 1.
Simplifying, we get -3x - 6 - 12 = x + 1.
Combining like terms, we have -4x - 18 = x + 1.
Adding 4x to both sides, we get -18 = 5x + 1.
Subtracting 1 from both sides, we have -19 = 5x.
Dividing both sides by 5, we get x = -19/5.

Therefore, the solutions to the equation are x = 7 and x = -19/5.

b) To solve this equation, we can again split it into two cases based on the sign of the expressions inside the absolute values.

Case 1: x - 2 and 3x + 5 are both positive
In this case, the equation becomes x - 2 = 3x + 5.
Subtracting x from both sides, we get -2 = 2x + 5.
Subtracting 5 from both sides, we have -7 = 2x.
Dividing both sides by 2, we get x = -7/2.

Case 2: x - 2 and 3x + 5 are both negative
In this case, the equation becomes -(x - 2) = -(3x + 5).
Simplifying, we get -x + 2 = -3x - 5.
Adding x to both sides, we have 2 = -2x - 5.
Adding 5 to both sides, we get 7 = -2x.
Dividing both sides by -2, we have x = -7/2.

Therefore, the solution to the equation is x = -7/2.

c) To solve this equation, we need to isolate the absolute value expression.

12 - 4*|x + 1/2| = 0
Subtracting 12 from both sides, we get -4*|x + 1/2| = -12.
Dividing both sides by -4, we have |x + 1/2| = 3.

Now we can split this equation into two cases based on the sign of the expression inside the absolute value.

Case 1: x + 1/2 is positive
In this case, the equation becomes x + 1/2 = 3.
Subtracting 1/2 from both sides, we get x = 2.5.

Case 2: x + 1/2 is negative
In this case, the equation becomes -(x + 1/2) = 3.
Simplifying, we get -x - 1/2 = 3.
Adding 1/2 to both sides, we have -x = 3.5.
Multiplying both sides by -1, we get x = -3.5.

Therefore, the solutions to the equation are x = 2.5 and x = -3.5.

d) To solve this equation, we can again split it into two cases based on the sign of the expressions inside the absolute values.

Case 1: x - 3 and 2x - 6 are both positive
In this case, the equation becomes x - 3 + 2(2x - 6) = 0.
Simplifying, we get x - 3 + 4x - 12 = 0.
Combining like terms, we have 5x - 15 = 0.
Adding 15 to both sides, we get 5x = 15.
Dividing both sides by 5, we have x = 3.

Case 2: x - 3 and 2x - 6 are both negative
In this case, the equation becomes -(x - 3) + 2(2x - 6) = 0.
Simplifying, we get -x + 3 + 4x - 12 = 0.
Combining like terms, we have 3x - 9 = 0.
Adding 9 to both sides, we get 3x = 9.
Dividing both sides by 3, we have x = 3.

Therefore, the solution to the equation is x = 3.

e) To solve this equation, we can again split it into two cases based on the sign of the expression inside the absolute value.

Case 1: 4 - x is positive
In this case, the equation becomes 4 - x = 8 - 2x.
Adding x to both sides, we get 4 = 8 - x.
Subtracting 8 from both sides, we have -4 = -x.
Multiplying both sides by -1, we get 4 = x.

Case 2: 4 - x is negative
In this case, the equation becomes -(4 - x) = 8 - 2x.
Simplifying, we get -4 + x = 8 - 2x.
Adding 2x to both sides, we have -4 + 3x = 8.
Adding 4 to both sides, we get 3x = 12.
Dividing both sides by 3, we have x = 4.

Therefore, the solutions to the equation are x = 4 and x = 4.
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