LH Quảng cáo: lazijsc@gmail.com

Bài tập  /  Bài đang cần trả lời

Giải bài có thưởng!

Cho tam giác ABC, trên tia đối của tia AB lấy D sao cho AD = AB

cho tam giác ABC ,trên tia đối của tia AB lấy D sao cho AD = AB.Lấy G thuộc AC sao cho AG = 1/3AC.Tia DG cắt BC ở E.Qua E vẽ đường thẳng song song với BD;Qua D vẽ đường thẳng song song với BC,2 đường này cắt nhau ở F.Gọi M là giao điểm của EF và CD.
CMR:M là trung điểm của đoạn thẳng DC
0 trả lời
Hỏi chi tiết
59
Tham khảo câu trả lời từ Trợ lý ảo Lazi
Ta có:
- Vì AD = AB nên tam giác ABD đều.
- Ta có AG = 1/3AC = 1/3(AB + BC) = 1/3(AD + DC) = 1/3(AB + DC) = 1/3(AB + 2BM) = 1/3(AB + 2DM) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3(AD + DC) = 1/3AC.
=> AG = 1/3AC = 1/3(AD + DC) = 1/3(AD + 2DM) = 1/3

Bạn hỏi - Lazi trả lời

Bạn muốn biết điều gì?

GỬI CÂU HỎI
Học tập không giới hạn cùng học sinh cả nước và AI, sôi động, tích cực, trải nghiệm
Bài tập Toán học Lớp 7 mới nhất
Trắc nghiệm Toán học Lớp 7 mới nhất

Hôm nay bạn thế nào? Hãy nhấp vào một lựa chọn, nếu may mắn bạn sẽ được tặng 50.000 xu từ Lazi

Vui Buồn Bình thường

Học ngoại ngữ với Flashcard

×
Trợ lý ảo Trợ lý ảo
×
Gia sư Lazi Gia sư