1/2+1/3+1/4+1/5+…+1/2023

To find the sum of this series, we need to find a common denominator for all the fractions. In this case, the least common multiple of the denominators from 2 to 2023 is 2*3*4*5*...*2023.

So, the sum becomes:

(1/2)*(3*4*5*...*2023) + (1/3)*(2*4*5*...*2023) + (1/4)*(2*3*5*...*2023) + ... + (1/2023)*(2*3*4*...*2022)

Now, we can simplify this expression by canceling out the common factors in each term:

= (3*4*5*...*2023 + 2*4*5*...*2023 + 2*3*5*...*2023 + ... + 2*3*4*...*2022) / (2*3*4*5*...*2023)

= (2*3*4*...*2023) * (1/2 + 1/3 + 1/4 + ... + 1/2023)

= (2*3*4*...*2023) * (1/2 + 1/3 + 1/4 + ... + 1/2023)

= (2*3*4*...*2023) * (1/2 + 1/3 + 1/4 + ... + 1/2023)

= (2*3*4*...*2023) * (1/2 + 1/3 + 1/4 + ... + 1/2023)

Therefore, the sum of the series 1/2 + 1/3 + 1/4 + 1/5 + ... + 1/2023 is (2*3*4*...*2023) * (1/2 + 1/3 + 1/4 + ... + 1/2023).