To solve this system of equations, we can first simplify the second equation by factoring out a common factor of "bc":

bc + abc = 53
bc(1 + a) = 53
bc = 53 / (1 + a)

Now we can substitute this expression for "bc" into the first equation:

a + 53 / (1 + a) = 136

Multiplying both sides by (1 + a) to clear the fraction:

a(1 + a) + 53 = 136(1 + a)
a + a^2 + 53 = 136 + 136a
a^2 + a - 83 = 0

Now we can solve this quadratic equation for "a" using the quadratic formula:

a = (-1 ± √(1^2 - 4*1*(-83))) / 2*1
a = (-1 ± √(1 + 332)) / 2
a = (-1 ± √333) / 2

Therefore, the solutions for "a" are:

a = (-1 + √333) / 2
a = (-1 - √333) / 2

Once we have the values of "a", we can substitute them back into the equation bc = 53 / (1 + a) to find the corresponding values of "bc".