The expression \(8x^3 + 27y^3\) can be factored using the sum of cubes formula. The sum of cubes is given by the formula:

\[
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
\]

In this case, we can identify \(a\) and \(b\) as follows:

- \(a = 2x\) (since \(8x^3 = (2x)^3\))
- \(b = 3y\) (since \(27y^3 = (3y)^3\))

Now we can apply the sum of cubes formula:

1. First, calculate \(a + b\):
\[
2x + 3y
\]

2. Next, calculate \(a^2 - ab + b^2\):
\[
a^2 = (2x)^2 = 4x^2
\]
\[
ab = (2x)(3y) = 6xy
\]
\[
b^2 = (3y)^2 = 9y^2
\]
Therefore,
\[
a^2 - ab + b^2 = 4x^2 - 6xy + 9y^2
\]

Putting it all together, we get:

\[
8x^3 + 27y^3 = (2x + 3y)(4x^2 - 6xy + 9y^2)
\]

So, the factorization of \(8x^3 + 27y^3\) is:

\[
(2x + 3y)(4x^2 - 6xy + 9y^2)
\]