To solve the equation \( 2 \times 5^{x+1} - 1100 = 6 \times 5^2 \), we can first simplify both sides.

Starting from the left side:

\[
2 \times 5^{x+1} - 1100
\]

We can rewrite \( 5^{x+1} \) as \( 5^x \times 5 \):

\[
2 \times 5 \times 5^x - 1100 = 10 \times 5^x - 1100
\]

Now our equation looks like:

\[
10 \times 5^x - 1100 = 6 \times 25
\]

Calculating \( 6 \times 25 \):

\[
6 \times 25 = 150
\]

Now we have:

\[
10 \times 5^x - 1100 = 150
\]

Next, we can add 1100 to both sides to isolate the term with \( 5^x \):

\[
10 \times 5^x = 150 + 1100
\]

Calculating the right side:

\[
150 + 1100 = 1250
\]

Now, dividing both sides by 10 to solve for \( 5^x \):

\[
5^x = \frac{1250}{10}
\]

Calculating the right side:

\[
5^x = 125
\]

Since \( 125 \) is \( 5^3 \), we can equate the exponents:

\[
x = 3
\]

Thus, the solution to the equation is:

\[
\boxed{3}
\]