BAI 1: TINH CAC DOAN THANG TRONG TAM GIAC ABC
1. Tinh do dai canh ACAp dung dinh ly
Pythagoras cho tam giac ABC vuong tai A:
AC^2 = BC^2 - AB^2 = 13^2 - 5^2 = 169 - 25 = 144
=>
AC = 12 cm2. Tinh do dai duong cao AHSu dung cong thuc: BC * AH = AB * AC
AH = (AB * AC) / BC = (5 * 12) / 13 =
60/13 cm (xap xi 4,62 cm)
3. Tinh do dai BH va CHAp dung he thuc luong:
- AB^2 = BH * BC => BH = AB^2 / BC = 5^2 / 13 = 25/13 cm (xap xi 1,92 cm)
- CH = BC - BH = 13 - 25/13 = 144/13 cm (xap xi 11,08 cm)
BAI 2: TAM GIAC ABC VUONG TAI A, DUONG CAO AH
a. Tinh do dai BH, BC, AC- Tinh BH: Ap dung dinh ly Pythagoras cho tam giac ABH vuong tai H:
BH^2 = AB^2 - AH^2 = 20^2 - 16^2 = 400 - 256 = 144
=> BH = 12 cm - Tinh BC:
BC = BH + HC = 12 + 64/3 = (36 + 64) / 3 = 100/3 cm (xap xi 33,33 cm) - Tinh AC: Ap dung dinh ly Pythagoras cho tam giac AHC vuong tai H:
AC^2 = AH^2 + HC^2 = 16^2 + (64/3)^2 = 256 + 4096/9 = (2304 + 4096) / 9 = 6400/9
=> AC = 80/3 cm (xap xi 26,67 cm)
b. Tinh chu vi tam giac ABCChu vi (P) = AB + BC + AC
P = 20 + 100/3 + 80/3 = 20 + 180/3 = 20 + 60 =
80 cmDap so:Bai 1: AC=12cm, AH=60/13cm, BH=25/13cm, CH=144/13cm.
Bai 2: BH=12cm, BC=100/3cm, AC=80/3cm, Chu vi=80cm.