1. Đặt số mol Al , Fe la x,y ta co 27x+56y=8.3
so mol H2 = 1.5x+y= 0.25
giai 2 phuong trinh tren ta co x= y= 0.1->khoi luong Fe = 5.6g, khoi luong Al = 2.7g
2) ta co so mol HCl phan ung = 2 lan so mol H2 -> so mol HCl phan ung = 2*0.25=0.5 mol-> the tich HCl tinh theo li thuyet =0.5/2=0.25(l)=250ml.Do dung du 10cm^3 nen the tich HCl thuc te =250+10=260ml(1ml=1cm^3)
3) dan khi clo vao dd A xay ra phan ung :
FeCl2+0.5Cl2->FeCl3
0.1-------------->0.1
sau phan ung dung dich co 0.1 mol FeCl3 va 0.1 mol AlCl3->khoi luong muoi khan khi co can =0.1*162.5+0.1*133.5=29.6g