Ta thấy:
BH/CH=9:16
=> BH=CH.9/16
ΔABC vuông A có AH⊥BC
=> AH^2=BH.CH
<=> 48^2=CH.CH.9/16
<=> CH^2=4096
<=> CH=64(cm)
=> BH=36 cm
BC=64+36=100cm
ΔABC vuông A có AH⊥BC
=> AB^2=BH.BC
=> AB^2=36.100=3600
AB=60cm
ΔABC vuông A
AB^2+AC^2=BC^2(pytago)
AC^2=100^2-60^2=6400
AC=80 cm