1)Bạn tham khảo:
3a−b+2ab−10=03a−b+2ab−10=0
⇒2ab−b+3a=10⇒2ab−b+3a=10 
⇒b(2a−1)+3a=10⇒b(2a−1)+3a=10 
⇒2b(2a−1)+6a=10.2⇒2b(2a−1)+6a=10.2
⇒2b(2a−1)+6a−3=20−3⇒2b(2a−1)+6a−3=20−3
⇒2b(2a−1)+3(2a−1)=17⇒2b(2a−1)+3(2a−1)=17 
⇒(2a−1)(2b+3)=17⇒(2a−1)(2b+3)=17 
⇒2a−1∈Ư(17)=⇒2a−1∈Ư(17)= { ±1;±17±1;±17 }

.) Nếu 2a−1=12a−1=1 thì 2b+3=172b+3=17 
⇒a=1;b=7⇒a=1;b=7
.) Nếu 2a−1=−12a−1=−1 thì 2b+3=−172b+3=−17
⇒a=0;b=−10⇒a=0;b=−10
.) Nếu 2a−1=172a−1=17 thì 2b+3=12b+3=1
⇒a=9;b=−1⇒a=9;b=−1
.) Nếu 2a−1=−172a−1=−17 thì 2b+3=−12b+3=−1
⇒a=−8;b=−2⇒a=−8;b=−2

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