1, (x^2+8x+12)(x^2+12x+32)+16
= (x^2+2x+6x+12)(x^2+4x+8x+32)+16
=[x(x+2)+6(x+2)][x(x+4)+8(x+4)]+16
=(x+2)(x+4)(x+6)(x+8)+16
=[(x+2)(x+8)][(x+4)(x+6)]+16
=(x^2+10x+16)(x^2+10x+24)+16
Đặt a=x^2+10x+20
khi đó ta có
(x^2+10x+16)(x^2+10x+24)+16
= (a+4)(a-4)+16
=a^2-16+16
=a^2
=(x^2+10x+20)^2
2, (x^2 + 6x + 8)(x^2 + 8x + 15) - 24
= (x^2 +2x+4x+ 8)(x^2 +3x+5x + 15) - 24
= [x(x+2)+4(x+2)][x(x+3)+5(x+3)]-24
=(x+2)(x+3)(x+4)(x+5)-24
=[(x+2)(x+5)] [(x+3)(x+4)]-24
= (x^2+7x+10)(x^2+7x+12)-24
Đặt a=x^2+7x+11 ta có
(x^2+7x+10)(x^2+7x+12)-24
= (a+1)(a-1)-24
= a^2-1-24
= a^2-25
=(a+5)(a-5)
=(x^2+7x+11+5)(x^2+7x+11-5)
= (x^2+7x+16)(x^2+7x+6)
3, (x^2 + 4x + 3)(x^2 + 6x + 8) - 24
= (x^2 + 1x +3x+ 3)(x^2 + 2x +4x + 8) - 24
= [x(x+1)+3(x+1)] [x(x+2)+4(x+2)] -24
= (x+1)(x+2)(x+3)(x+4)-24
= [(x+1)(x+4)] [(x+2)(x+3)] -24
= (x^2+5x+4)(x^2+5x+6)-24
Đặt a=x^2+5x+5 ta có
(x^2+5x+4)(x^2+5x+6)-24
= (a+1)(a-1)-24
= a^2-1-24
= a^2-25
= (a+5)(a-5)
= (x^2+5x+5+5)(x^2+5x+5-5)
= x(x^2+5x+10)(x+5)