I=6^2+6^3+6^4....6^100 K=(-8)+(-8)^2+(-8)^3+.....+(-8)^19+(-8)^20 I=6^2+6^3+6^4....6^100 K=(-8)+(-8)^2+(-8)^3+.....+(-8)^19+(-8)^20 A=2^3+2^4+2^5+...2^99 B=3^2+3^3+3^4+3^5+....3^100 C=4^0+4^2+4^4...4^98+4^100
Tham khảo câu trả lời từ Trợ lý ảo Lazi To find the values of I, K, A, B, and C, we can use the formulas for the sum of a geometric series. For I, we have a geometric series with a common ratio of 6 and the first term being 6^2. The sum of this series is given by the formula: I = (6^2 * (1 - 6^99)) / (1 - 6) = (36 * (1 - 6^99)) / (-5) For K, we have a geometric series with a common ratio of -8 and the first term being -8. The sum of this series is given by the formula: K = (-8 * (1 - (-8)^20)) / (1 - (-8)) = (-8 * (1 - 8^20)) / 9 For A, we have a geometric series with a common ratio of 2 and the first term being 2^3. The sum of this series is given by the formula: A = (2^3 * (1 - 2^97)) / (1 - 2) = (8 * (1 - 2^97)) / (-1) For B, we have a geometric series with a common ratio of 3 and the first term being 3^2. The sum of this series is given by the formula: B = (3^2 * (1 - 3^99)) / (1 - 3) = (9 * (1 - 3^99)) / (-2) For C, we have a geometric series with a common ratio of 4 and the first term being 4^0. The sum of this series is given by the formula: C = (4^0 * (1 - 4^100)) / (1 - 4) = (1 * (1 - 4^100)) / (-3) Now we can calculate the values of I, K, A, B, and C using these formulas.