(2xa-15) mũ 3 =(2 mũ 3 x 3 mũ 3-2 mũ 3 x 2 mũ 2) : 19 x 2

To solve this equation, we need to simplify both sides and then solve for the variable.

Starting with the left side of the equation:
(2xa - 15)^3

Using the formula for the cube of a binomial, we can expand this expression:
(2xa)^3 - 3(2xa)^2(15) + 3(2xa)(15)^2 - (15)^3
= 8x^3a^3 - 3(4x^2a^2)(15) + 3(2xa)(225) - 3375
= 8x^3a^3 - 180x^2a^2 + 675xa - 3375

Now let's simplify the right side of the equation:
(2^3 x 3^3 - 2^3 x 2^2) / (19 x 2)
= (8 x 27 - 8 x 4) / (19 x 2)
= (216 - 32) / (38)
= 184 / 38
= 92 / 19

Now we can set the left side equal to the right side and solve for x and a:
8x^3a^3 - 180x^2a^2 + 675xa - 3375 = 92 / 19

This equation is not solvable without additional information or constraints on the variables x and a.