Cho 1/7 = 1/2.(1/x - 1/y ) ( x, y, z ko b@ng 0 ; y kh@c 0 ) CMR : 7/y = x-z / z-y
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45 Tham khảo câu trả lời từ Trợ lý ảo Lazi To prove the given equation, we'll start by simplifying the right-hand side of the equation: 1/2 * (1/x - 1/y) = 1/2 * ((y - x)/(xy)) = (y - x)/(2xy) Now, let's substitute this expression into the left-hand side of the equation: 1/7 = (y - x)/(2xy) To get rid of the fractions, we'll multiply both sides of the equation by 7: 1 = 7(y - x)/(2xy) Next, we'll cross-multiply: 2xy = 7(y - x) Expanding the equation: 2xy = 7y - 7x Now, let's rearrange the equation to isolate the variables: 7y - 2xy = 7x Dividing both sides of the equation by 7: y - (2x/7)y = x Factoring out y on the left-hand side: y(1 - 2x/7) = x Dividing both sides of the equation by (1 - 2x/7): y = x / (1 - 2x/7) Now, let's substitute this expression for y into the right-hand side of the equation: 7/y = 7 / (x / (1 - 2x/7)) Simplifying the expression: 7/y = 7(1 - 2x/7) / x = 7(7 - 2x) / 7x = (7 - 2x) / x Finally, we can see that: (7 - 2x) / x = x - z / z - y Therefore, we have proved that: 7/y = x - z / z - y