To find the value of the expression (1+3+5+....+27)×(333×6-6×333), we first need to calculate the sum of the odd numbers from 1 to 27.

The sum of an arithmetic series can be found using the formula Sn = (n/2)(a + l), where Sn is the sum of the series, n is the number of terms, a is the first term, and l is the last term.

In this case, the first term (a) is 1, the last term (l) is 27, and the number of terms (n) can be calculated using the formula n = (l - a)/2 + 1.

n = (27 - 1)/2 + 1
n = 26/2 + 1
n = 13 + 1
n = 14

Now we can calculate the sum (Sn) using the formula Sn = (n/2)(a + l).

Sn = (14/2)(1 + 27)
Sn = 7(28)
Sn = 196

Now we can substitute this value into the expression:

(1+3+5+....+27)×(333×6-6×333) = 196 × (333×6-6×333)

Next, we can simplify the expression inside the parentheses:

333×6-6×333 = 1998 - 1998
333×6-6×333 = 0

Now we can substitute this value into the expression:

196 × 0 = 0

Therefore, the value of the expression (1+3+5+....+27)×(333×6-6×333) is 0.