Tham khảo câu trả lời từ Trợ lý ảo Lazi To find the value of the given expression, we can start by simplifying each term and then adding them together. The expression can be written as: A = 1/2.6 + 1/3.8 + 1/4.10 + 1/5.12 + ... + 1/499.1000 Now, let's simplify each term: 1/2.6 = 1/(2*6) = 1/12 1/3.8 = 1/(3*8) = 1/24 1/4.10 = 1/(4*10) = 1/40 1/5.12 = 1/(5*12) = 1/60 We can see that each term is in the form 1/(n*(n+4)), where n is the numerator and n+4 is the denominator. Now, let's find a pattern for the terms: 1/12, 1/24, 1/40, 1/60, ... We can observe that the numerator is always 1, and the denominator follows the pattern n*(n+4). So, the expression can be written as: A = 1/12 + 1/24 + 1/40 + 1/60 + ... + 1/(499*(499+4)) Now, let's find the common denominator for all the terms: The common denominator is the least common multiple (LCM) of the denominators, which is 12*24*40*60*...*(499*(499+4)). To simplify the calculation, we can divide each denominator by 4: 12/4 = 3 24/4 = 6 40/4 = 10 60/4 = 15 So, the common denominator becomes: 3*6*10*15*...*(499*(499+4)) Now, let's simplify the expression: A = (1/12)*(3/3) + (1/24)*(6/6) + (1/40)*(10/10) + (1/60)*(15/15) + ... + (1/(499*(499+4)))*((499*(499+4))/(499*(499+4))) A = (3/36) + (6/144) + (10/400) + (15/900) + ... + (499*(499+4))/(499*(499+4)) A = (3 + 6 + 10 + 15 + ... + (499*(499+4)))/(499*(499+4)) Now, let's find the sum of the numerator: The sum of the first n terms of the series 1, 2, 3, 4, ... is given by the formula n*(n+1)/2. So, the sum of the first 499 terms is 499*(499+1)/2 = 499*500/2 = 249500. Now, let's substitute this value into the expression: A = 249500/(499*(499+4)) A = 249500/(499*503) A = 249500/250997 A ≈ 0.993