To solve the equation \( x(2x - 10) = 4x(x - 6) \), follow these steps:

1. Distribute both sides of the equation:
\[ x(2x - 10) = 2x^2 - 10x \]
\[ 4x(x - 6) = 4x^2 - 24x \]

2. Set the equations equal to each other:
\[ 2x^2 - 10x = 4x^2 - 24x \]

3. Move all terms to one side to set the equation to 0:
\[ 2x^2 - 10x - 4x^2 + 24x = 0 \]
\[ -2x^2 + 14x = 0 \]

4. Factor out the common term:
\[ -2x(x - 7) = 0 \]

5. Set each factor equal to zero:
\[ -2x = 0 \quad \text{or} \quad x - 7 = 0 \]

6. Solve for \( x \):
\[ x = 0 \quad \text{or} \quad x = 7 \]

So, the solutions to the equation \( x(2x - 10) = 4x(x - 6) \) are \( x = 0 \) and \( x = 7 \).