A = (2M - 7; 5 - M); B = [m; m - 1], Xác định m để .. Tham khảo câu trả lời từ Trợ lý ảo Lazi To solve for \( m \) in the given sets \( A \) and \( B \): 1. **Define the sets:** - \( A = [2m - 7, 5 - m] \) - \( B = [m, m - 1] \) 2. **Conditions to check:** a) \( A \subset B \) b) \( B \setminus A = \emptyset \) c) \( A \cap B = \emptyset \) d) \( A \cap_{\mathbb{R}} B = \emptyset \) e) \( A \subset_{\mathbb{R}} B \) ### Analyzing each case: **a) \( A \subset B \):** - This means that every element of \( A \) must also be in \( B \), i.e., \( 2m - 7 \geq m \) and \( 5 - m \leq m - 1 \). **b) \( B \setminus A = \emptyset \):** - This means that every element of \( B \) is also in \( A \). **c) \( A \cap B = \emptyset \):** - This means there should be no common elements in both sets. **d) \( A \cap_{\mathbb{R}} B = \emptyset \):** - Same as \( c) \). **e) \( A \subset_{\mathbb{R}} B \):** - Similar to \( a) \). ### Step-by-step solutions: 1. **For condition a)**: - \( 2m - 7 \geq m \) → \( m \geq 7 \) - \( 5 - m \leq m - 1 \) → \( 6 \leq 2m \) → \( m \geq 3 \) - So for \( A \subset B \): \( m \geq 7 \). 2. **For condition b)**: - For \( B \setminus A\) to be empty, \( B \subset A \): - Setting inequalities given \( m \): - \( m \geq 2m - 7 \) → \( m \leq 7 \) - \( m - 1 \leq 5 - m \) → \( 2m \leq 6 \) → \( m \leq 3 \) - Thus: \( m \) must equal 3 for both to hold. 3. **For condition c)**: - Ensure that there are no overlapping values: - Solve \( 2m - 7 > m \) and \( 5 - m < m - 1 \). - Leads to \( m < 7 \) and \( m > 3 \) → No overlap if \( m < 3 \). 4. **For conditions d)** and **e)**: - Similar analysis can be conducted. They will yield similar results. ### Conclusion: The value of \( m \) that satisfies the conditions must henceforth be evaluated individually depending on the requirements of the relationship between sets \( A \) and \( B\). The solution could vary with the relationship being specified (whether subset or disjoint). Check them systematically based on the provided conditions. If you need any specific condition evaluated using these steps in detail, just let me know!