a) Ta có: \(V = \frac{4}{3}\pi {R^3},\) suy ra \(R = \sqrt[3]{{\frac{{4\pi }}}} = \sqrt[3]{{\frac{{4\pi }}}} = \sqrt[3]{{\frac{{2\pi }}}}\) (m);

Khi đó, \(S = 4\pi {R^2} = 4 \cdot \pi \cdot {\left( {\sqrt[3]{{\frac{{2\pi }}}}} \right)^2} \approx 284\) (m²).

b) Ta có: \(V = \frac{4}{3}\pi {R^3},\) suy ra \(R = \sqrt[3]{{\frac{{4\pi }}}} = \sqrt[3]{{\frac{{4\pi }}}} = \sqrt[3]{{\frac{{2\pi }}}}\) (dm);

Khi đó, \(S = 4\pi {R^2} = 4 \cdot \pi \cdot {\left( {\sqrt[3]{{\frac{{2\pi }}}}} \right)^2} \approx 192\) (dm²).

c) Ta có: \(V = \frac{4}{3}\pi {R^3},\) suy ra \[R = \sqrt[3]{{\frac{{4\pi }}}} = \sqrt[3]{{\frac{{4\pi }}}} = \sqrt[3]{{\frac{{2\pi }}}}\] (cm);

Khi đó, \(S = 4\pi {R^2} = 4 \cdot \pi \cdot {\left( {\sqrt[3]{{\frac{{2\pi }}}}} \right)^2} \approx 76\) (cm²).