It looks like you're trying to solve the equation \( \frac{2x - 1}{x + 3} = -\frac{3}{42} \).

Let's start by simplifying the right side:

1. Simplify \( -\frac{3}{42} \) to \( -\frac{1}{14} \).

Now, we have the equation:

\[
\frac{2x - 1}{x + 3} = -\frac{1}{14}
\]

2. To eliminate the fraction, cross-multiply:

\[
14(2x - 1) = -1(x + 3)
\]

3. Distribute both sides:

\[
28x - 14 = -x - 3
\]

4. Now, move all terms involving \( x \) to one side and constant terms to the other:

\[
28x + x = -3 + 14
\]

5. Combine like terms:

\[
29x = 11
\]

6. Solve for \( x \):

\[
x = \frac{11}{29}
\]

So the solution to the equation is:

\[
\boxed{\frac{11}{29}}
\]

If you also meant to solve the second part of your equation with a similar structure, just let me know!