It looks like you're trying to solve a problem involving divisibility or factors, but your expression is not clear. Let's break down the problem into a clearer statement. Are you referring to the expressions \( (2x - 1) \) and \( (x + 3) \)?

If you want \( 2x - 1 \) to be divisible by \( x + 3 \), you are essentially looking for:

\[
2x - 1 \equiv 0 \pmod{x + 3}
\]

To find when this condition is satisfied, you would perform polynomial division or simply check when the remainder is zero in such division.

1. Perform the division of \( 2x - 1 \) by \( x + 3 \):
- Divide the leading term of the dividend \( 2x \) by the leading term of the divisor \( x \) to get the first term of the quotient, which is \( 2 \).
- Multiply \( x + 3 \) by \( 2 \) to get \( 2x + 6 \).
- Subtract \( 2x + 6 \) from \( 2x - 1 \):
\[
(2x - 1) - (2x + 6) = -7
\]

The remainder is \(-7\). Therefore, \( 2x - 1 \) is not divisible by \( x + 3 \) for all integer values of \( x \). For divisibility, the remainder must be zero, which means finding values of \( x \) that satisfy:
\[
2x - 1 = k(x + 3)
\]
for some integer \( k \).

2. To ensure divisibility, solve the equation:
\[
2x - 1 + 7 = 0 \Rightarrow 2x = 1 - 7 \Rightarrow 2x = -6 \Rightarrow x = -3
\]

Thus, \( x = -3 \) should satisfy the condition.

If there is more to the original problem or more expressions, please clarify the complete problem statement.