bài 1
AgNO3 + HCl = AgCl + HNO3
0,5............0,5.......0,5.......0,5
nAgNO3=0,5 mol
nHCl =0,3.2=0,6 mol
Theo PTPU => HCl dư
nAgCl=0,5 mol
nHNO3=0,5 mol
=> Cm HNO3= 0,5:0,8=0,625M
C% HNO3= (0,5.63):(500.1,2+300.1,5-0,5.143,5)=3,22%