a,Theo bra:nAl=5,4/27=0,2 mol
PTHH:2Al+3H2SO4=>Al2(SO4)3+3H2
Theo PTHH:nH2=1,5nAl=1,5 x 0,2=0.3 mol
=>V H2=0,15 x 22 4=3,36 l
b,Theo PTHH:nH2SO4=1,5nAl=1,5 x 0,2=0.3 mol
=>CM dd H2SO4=0,3/0,1=3M
Theo PTHH:nAl2(SO4)3=2nAl=2 x 0,2=0,4 mol
=>CM dd Al2(SO4)3=0,4/0.1=4 M