nNO2=0,15 mol

PT electron: nAg*1=nNO2*1=0,15 mol

=> nAnđ=nAg/2=0,15/2=0,075 mol

=> MAnđ=5,4/0,075=72

Gọi CT CxHy-CHO

=> MCxHy + MCHO =72

<=> MCxHy + 29 =72 => MCxHy=43 => C3H7-

=> C3H7-CHO

CH3-CH2-CH2-CHO : Butanal

CH3-CH(CH3)-CHO : 2-metylpropanal

b. C3H7-CHO + H2 -> C4H9OH

0,075------------------->0,075

=> mC4H10O=0,075*74=5,55g