nCu=12,288/64=0,192mol
nCl2=17,04/71=0,24mol
PTHH : Cu+Cl2→CuCl2
Vì 0,192/1 < 0,24/1
=> Cu hết, Cl2 dư
=> nCuCl2 = nCu = 0,192
mCuCl2=0,192.135=25,92g

nCu=12,288/64=0,192mol nCl2=17,04/71=0,24mol

PTHH Cu+Cl2→CuCl2

mCuCl2=0,192.135=25,92g